Respuesta :
we have
f(x) = a(x – h)² + k
we know the vertex v(5,3)
substitute in the values for h and k
f(x) = a(x – 5)² + 3
Use another point and substitute in values for x and f(x).
for the point (6,5)
Solve for a.
5 = a(6 – 5)2 + 3-------------- > 5=a+3-------------> a=2
The function is f(x)=a(x – h)2 + k-------- > 2(x – 5)² + 3
f(x)= 2(x – 5)² + 3-------- > 2[x²-10x+25]+3=2x²-20x+50+3=2x²-20x+53
f(x)=2x²-20x+53
the answer is f(x)= 2(x – 5)² + 3----------------- > (f(x)=2x²-20x+53)
f(x) = a(x – h)² + k
we know the vertex v(5,3)
substitute in the values for h and k
f(x) = a(x – 5)² + 3
Use another point and substitute in values for x and f(x).
for the point (6,5)
Solve for a.
5 = a(6 – 5)2 + 3-------------- > 5=a+3-------------> a=2
The function is f(x)=a(x – h)2 + k-------- > 2(x – 5)² + 3
f(x)= 2(x – 5)² + 3-------- > 2[x²-10x+25]+3=2x²-20x+50+3=2x²-20x+53
f(x)=2x²-20x+53
the answer is f(x)= 2(x – 5)² + 3----------------- > (f(x)=2x²-20x+53)
Here we want to write the quadratic function for the parabola shown in vertex form.
We will get the function: f(x) = 2*(x - 5)^2 + 3
So the general function of a parabola with vertex (h, k) and leading coefficient a is:
f(x) = a*(x - h)^2 + k
Here, we know the formula:
f(x) = a*(x - 5)^2 + 3
where:
- h = 5
- k = 3
So the vertex is the point (5, 3), and we only must find the value of a to completely determine the parabola's function
We also know that:
f(6) = 5
So we can solve:
5 = a*(6 - 5)^2 + 3
5 = a*(1)^2 + 3
5 = a + 3
5 - 3 = a = 2
So we just found the value of a, replacing this on the parabola's function we get:
f(x) = 2*(x - 5)^2 + 3
If you want to learn more about parabolas, you can read:
https://brainly.com/question/1480401