Question

PLEASE HELP! 30 POINTS! What are the zeros of the function?


f(t)=t^2-13t+36

Enter your answers in the boxes.

Answer 1

Solve the equation
$f(t) = 0$
So we have:
${t}^{2} - 13t + 36$
Factor, 2 numbers of which the sum is -13 and multiplying gives 36, these two are -4 and -9
So solve:
$(x - 4)(x - 9) = 0$
The solutions:
4 and 9