Respuesta :
For independent events [tex]X,Y[/tex], [tex]\mathbb P(X\cap Y)=\mathbb P(X)\times\mathbb P(Y)[/tex].
So
[tex]\mathbb P(X\cap Y)=\dfrac13\times\dfrac12=\dfrac16[/tex]
So
[tex]\mathbb P(X\cap Y)=\dfrac13\times\dfrac12=\dfrac16[/tex]
Answer: a. [tex]\dfrac{1}{6}[/tex]
Step-by-step explanation:
Given : Events X and Y are independent.
The probability of X occurring is [tex]\dfrac{1}{3}[/tex].
The probability of Y occurring is [tex]\dfrac{1}{2}[/tex].
Since both events are independent, then we have
[tex]\text{P(X and Y)}=\text{P(X)}\times \text{P(Y)}\\\\\Rightarrow\ \text{P(X and Y)}=\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{1}{6}[/tex]
Hence, [tex]\text{P(X and Y)}=\dfrac{1}{6}[/tex]
Thus , (a.) is the correct option.