Respuesta :
Answer:
39.98 liters
Explanation:
The first you should know: At STP , 1 mole of any gas takes up 22.4 Liters of volume.
After, you will find the molecular weight (MW) of N2 with help of a periodic table.
Then N= 14,007 g
So:
N2 = 14,007 * 2
MW =28,014 g/ mol N2
Now you will start with the data of 50 grams of N2 and you obtain:
50 g N2 x 1 mol N2 x 22.4 L N2 = 39.98 L at STP 28,014 g N2 1 mol N2
50 g of nitrogen, N₂ has a volume of 40 L at standard temperature and pressure (stp)
We'll begin by calculating the number of mole in 50 g of N₂. This can be obtained as follow:
Mass of N₂ = 50 g
Molar mass of N₂ = 2 × 14 = 28 g/mol
Mole of N₂ =?
Mole = mass / molar mass
Mole of N₂ = 50 / 28
Mole of N₂ = 1.786 mole
Finally, we shall obtain the volume occupied by 1.786 mole of N₂ at STP. This can be obtained as follow:
At standard temperature and pressure (STP)
1 mole of N₂ = 22.4 L
Therefore,
1.786 mole of N₂ = 1.786 × 22.4
1.786 mole of N₂ = 40 L
Therefore, 50 g of N₂ occupies 40 L at standard temperature and pressure (STP).
Learn more: https://brainly.com/question/2493827