Respuesta :

Answer:

39.98 liters

Explanation:

The first you should know:  At STP , 1 mole of any  gas takes up 22.4 Liters of volume.

After, you will find the molecular weight (MW) of N2 with help of a periodic table.

Then N= 14,007 g      

So:  

N2 = 14,007 * 2      

MW =28,014 g/ mol N2  

Now you will start with the data of 50 grams of N2 and you obtain:    

50 g N2  x 1 mol N2    x  22.4 L N2      =  39.98 L at STP                                 28,014 g N2        1 mol N2      

50 g of nitrogen, N₂ has a volume of 40 L at standard temperature and pressure (stp)

We'll begin by calculating the number of mole in 50 g of N₂. This can be obtained as follow:

Mass of N₂ = 50 g

Molar mass of N₂ = 2 × 14 = 28 g/mol

Mole of N₂ =?

Mole = mass / molar mass

Mole of N₂ = 50 / 28

Mole of N₂ = 1.786 mole

Finally, we shall obtain the volume occupied by 1.786 mole of N₂ at STP. This can be obtained as follow:

At standard temperature and pressure (STP)

1 mole of N₂ = 22.4 L

Therefore,

1.786 mole of N₂ = 1.786 × 22.4

1.786 mole of N₂ = 40 L

Therefore, 50 g of N₂ occupies 40 L at standard temperature and pressure (STP).

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