The first team of workers received 50 kg of cement less than the second team. for every hour of work the first team was using 150 kg of cement, while the second team was using 200 kg. in three hours the first team had 1.5 times as much remaining cement as the second team. how much cement was delivered to each team of workers

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the first team of workers received 50kg of cement less than second team.every hour of work first team was using 150kg of cement while second team used 200kg,in 3 hours the first team had 1.5 times as much remaining cement as second team.how much cement was delivered to each team.:Let a = amt of cement delivered to the 2nd teamthen(a-50) = amt delivered to the 1st team:1st team remains = 1.5 times 2nd team remains(a-50) - 3(150) = 1.5[a - 3(200)]a - 50 - 450 = 1.5(a - 600)a - 500 = 1.5a - 900-500 + 900 = 1.5a - a400 = .5aa = 800 kg delivered to the 2nd teamthen800 - 50 = 750 kg for the 1st team::Check this by find the actual amt each had remainingTeam 1: 750 - 3(150) = 300 kgTeam 2: 800 - 3(200) = 200 kg300 is 1.5*200
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