We can find the slope of the equation by using the slope formula:
[tex]\sf m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
For points in the form of [tex]\sf (x_1,y_1),(x_2,y_2)[/tex]. Let's use (0,0) and (11, 2).
[tex]\sf m=\dfrac{2-0}{11-0}[/tex]
[tex]\sf m=\dfrac{2}{11}[/tex]
This is our slope. Now let's find the y-intercept. The y-intercept is what 'x' is when 'y' equals 0. In our table, when 'y' is 0, 'x' is also 0. So our y-intercept is 0. Now let's plug this information into slope-intercept form:
[tex]\sf y=mx+b[/tex]
Where 'm' is the slope and 'b' is the y-intercept.
[tex]\sf y=\dfrac{2}{11}x+0[/tex]
Simplify:
[tex]\sf y=\boxed{\sf\dfrac{2}{11}x}[/tex]
