A man has a recessive genetic condition that neither of his parents expressed. His wife does not have this condition. However, she is a carrier. Based on this information, which Punnett square correctly predicts the probability that their children will have this genetic condition?

A man has a recessive genetic condition that neither of his parents expressed His wife does not have this condition However she is a carrier Based on this infor class=

Respuesta :

the most likely answer is the third because he is dominate in this Gene and his wife is a carrier so she's only 'half dominate' if you will.

Answer:

Option A

Explanation:

Let the genetic condition/trait be represented by alphabet A such that "A" represents the dominant genetic trait while "a" represent the recessive genetic trait.

Hence, man having the recessive genetic condition will have genotype "aa"

while female only being a carrier will have "Aa" genotype.

Thus, when the cross is carried out between the recessive man and the carrier woman, the following offspring are produced

Aa x aa

Aa, Aa, aa, aa

Hence the correct punnet square is represented in option A

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