Respuesta :
[tex]\bf ~~~~~~~~~~~~ \textit{Amortized Loan Value}
\\\\
pymt=P\left[ \cfrac{\frac{r}{n}}{1-\left( 1+ \frac{r}{n}\right)^{-nt}} \right]
\\\\\\
~~~~~~
\begin{cases}
P=
\begin{array}{llll}
\textit{original amount deposited}\\
\end{array}\to &250000\\
pymt=\textit{periodic payments}\\
r=rate\to 5.4\%\to \frac{5.4}{100}\to &0.054\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{since the payments are}\\
\textit{monthly, then twelve}
\end{array}\to &12\\
t=years\to &30
\end{cases}
[/tex]
[tex]\bf pymt=250000\left[ \cfrac{\frac{0.054}{12}}{1-\left( 1+ \frac{0.054}{12}\right)^{-12\cdot 30}} \right] \\\\\\ pymt=250000\left[ \cfrac{0.0045}{1-\left( 1.0045\right)^{-360}} \right] \\\\\\ pymt\approx 250000\left[ \cfrac{0.0045}{0.80138080852472389274} \right][/tex]
[tex]\bf pymt=250000\left[ \cfrac{\frac{0.054}{12}}{1-\left( 1+ \frac{0.054}{12}\right)^{-12\cdot 30}} \right] \\\\\\ pymt=250000\left[ \cfrac{0.0045}{1-\left( 1.0045\right)^{-360}} \right] \\\\\\ pymt\approx 250000\left[ \cfrac{0.0045}{0.80138080852472389274} \right][/tex]
