Question

A university football stadium has 1/6 of its students' seats in the end zones. If tickets are randomly selected and mailed to students, what is the probability that a certain student would get end zone seats at all 5 home games?

Answer 1

Answer:

1/7,776

Step-by-step explanation:

the odds of getting an end zone seat once is 1/6 so you multiply that by itself 5 times to get your answer.

1/6 x 1/6 x 1/6 x 1/6 x 1/6 x 1/6 = (1/6)^5 = 1/7,776.

Answer 2

The probability that a certain student would get end zone seats at all 5 home games is $\frac{1}{7776}$

What is Probability?

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true.

Given,

A university football stadium has 1/6 of its students' seats in the end zones

Probability = Number of Favorable outcome / Number of total outcome

Probability that a certain student would get end zone = $\frac{1}{6}$

Probability that a certain student would get end zone in 5 game = $(\frac{1}{6} )(\frac{1}{6} )(\frac{1}{6} )(\frac{1}{6} )(\frac{1}{6} )=\frac{1}{7776}$

Hence, the probability that a certain student would get end zone seats at all 5 home games $\frac{1}{7776}$

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