Question

Here is the sample space for three tosses of a coin.
{HHH, HHT, HTH, HTT, THH, THT, TTH, THT}
Calculate the probability that this compound event will yield a result of 2 heads and 1 tail (in any order)
A. 0.125
B. 0.25
C. 0.333
D. 0.375

Answer 1

Assuming the coin is fair, the probability of the coin toss resulting in H is $p=\dfrac12$. So the probability of getting two Hs, in any order, is

$\dbinom32p^2(1-p)=\dfrac38=0.375$

Answer 2

I just finished this test a second ago the answer is 0.125 so it is option A