Question

A gas sample has a volume of 178 mL at 0.00oC.The temperature is raised at constant pressure until the volume reaches 211 mL. What is the temperature of that gas sample at this volume?

Answer 1

V₁ = 178 mL                  - initial volume 
T₁ = 0 ⁰C = 273K          - initial temperature
V₂ = 211 mL                   - final volume
T₂ =?                              - final temperature

According to Charles's law when pressure is constant the Kelvin temperature and the volume will be directly related:

V₁/T₁=V₂/T₂

178/273=211/T₂

0.65=211/T₂

T₂=324K= 51⁰C

Answer 2

The temperature of the gas will be 324K or $\rm \bold{51^\cdot C}$ when volume reaches 211 mL.

Charle's law stated that the volume occupied by fixed amount of gas is directly proportional to the temperature,while  pressure is constant.

 $\rm \bold{\frac{V_1}{T_1} =\frac{V_2}{T_2}}$

Where,

$\rm \bold V_1$ is initial volume = 178mL

$\rm \bold {V_2}$ is final volume = 211mL

$\rm \bold{ T_1}$ is initial temperature = $\rm \bold{0.00^\cdot C}$ = 273K

$\rm \bold {T_2}$ is final temperature = ?

Put the values,

$\rm \bold{\frac{178}{273} =\frac{211}{T_2}}\\\\\rm \bold{T_2=324 K}$

Hence, we can conclude that the temperature of the gas will be 324K or $\rm \bold{51^\cdot C}$ when volume reaches 211 mL.

To know more about Charle's law, you can refer to the link:

https://brainly.com/question/16927784?referrer=searchResults