Respuesta :
Answer is: temperature of helium is -296,95°C.
The temperature T in degrees Celsius (°C) is equal to the temperature T in Kelvin (K) minus 273,15: T(°C) = T(K) - 273.15.
T(He) = 4,2 K.
T(He) = 4,2 K - 273,15.
T(He) = -268,95°C.
The Celsius scale was based on 0°C for the freezing point of water and 100°C for the boiling point of water at 1 atm pressure.
The temperature T in degrees Celsius (°C) is equal to the temperature T in Kelvin (K) minus 273,15: T(°C) = T(K) - 273.15.
T(He) = 4,2 K.
T(He) = 4,2 K - 273,15.
T(He) = -268,95°C.
The Celsius scale was based on 0°C for the freezing point of water and 100°C for the boiling point of water at 1 atm pressure.
The temperatur e of Helium in °C = -268.8 °
Further explanation
Temperature is one of the principal quantities that shows the degree of heat or cold from an object / space
Temperature is used as a guide to the level of heat energy from objects
Temperature measures thermal energy
The temperature of an object also depends on the kinetic energy of the object's molecules
Temperature cannot be measured by the surface of the hand because it is not accurate but can be measured by a thermometer. Temperature units include Celsius, Fahrenheit, Reamur or Kelvin
Boiling point and freezing point of Temperature units;
- 1. Celsius
Boiling point : 100 °C
Freezing point: 0 °C
- 2. Reamur
Boiling point : 80 °R
Freezing point: 0 °R
- 3. Fahrenheit
Boiling point : 212 °F
Freezing point: 32 °F
- 4. Kelvin
Boiling point : 373 °K
Freezing point: 273 °K
Whereas the temperature conversion is
°F = (9/5) °C + 32
°R = (4/5) °C
°K = °C + 273
°C = 5/9 (°F-32)
°R = 4/9 (°F-32)
°K = 5/9 (°F-32) + 273
°C = °K - 273
°R = 4/5 (°K-273)
°F = 9/5 (°K-273) + 32
°C = (5/4) °R
°F = (9/4) °R + 32
°K = °C + 273
°K = (5/4) °R + 273
Helium at 4.2 K, then the temperature in C :
C = K - 273
C = 4.2 - 273
C = -268.8 C
Learn more
The difference between temperature and heat
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relationships among temperature, heat, and thermal energy.
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When heat is added to a substance
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