Question

What is the density of a piece of metal in g/cm3 if its mass is determined to be 42.20 g and it is in the shape of a cube, with edge length of 2.50 cm?

Answer 1

It's a cube so the volume = edge^3
Volume = 2.5^3 cm^3 = 15.625 cm^3

density = mass / volume = 42.20 / 15.625 = 2.70 You have 3 places of accuracy.

density of object = 2.70 grams / cm^3 <<<<=== answer.

Answer 2

Answer : The density of a piece of metal is $2.7008g/cm^3$

Explanation :

To calculate the volume of cube, we use the formula:

$V=a^3$

where,

a = edge length of cube

Given :

Edge length of cube = 2.50 cm

Volume of cube = $(2.50cm)^3=15.625cm^3$

Given :

Mass of metal = 42.20 g

To calculate density of a substance, we use the equation:

$Density=\frac{Mass}{Volume}$

Putting values in above equation, we get:

$\text{Density of metal}=\frac{42.20g}{15.625cm^3}=2.7008g/cm^3$

Hence, the density of a piece of metal is $2.7008g/cm^3$