The area of the triangle shown is represented by A= square root of s(s-10)(s-7)(s-5), where s is equal to half the perimeter. What is the height of the triangle? Round your answer to the nearest tenth.
It should be 3.25 S is half the perimeter, so .5*(7+5+10)=11 Plug in 11 and you get A=sqrt(264) A also is half base times height sqrt(264)=.5*10*h h=sqrt(264)/5 h=3.25