Question

8- 2 to the root of 4+8*2^3-(3+14-5)/12
I don't know if this makes sense but I need help with it.

Answer 1

$8-2^{ \sqrt{4}} +8 \times 2^{3} -\frac{3+14-5}{12}$
$= 8 -2^{2} +8 \times 8 -\frac{12}{12}$
$= 8-4+64-1 = 67$