Question

how many grams of ammonia would be formed from the complete reaction of 4.50 moles hydrogen

Answer 1

(4.50 mol H2) x (2 mol NH3 / 3 mol H2) x (17.03056 g NH3/mol) = 51.1 g NH3

Answer 2

Answer:

51 grams of ammonia would be formed.

Explanation:

$3H_2+N_2\rightarrow 2NH_3$

Moles of hydrogen gas = 4.50 moles

According to reaction, 3 moles of hydrogen gas gives 2 moles of ammonia gas.

Then 4.50 moles of hydrogen gas will give:

$\frac{2}{3}\times 4.50 mol=3.00 mol$of ammonia

Mass of 3.00 moles of ammonia:

$17 g/mol\times mol=51 g$

51 grams of ammonia would be formed.