Calculate the pH of a solution in which [H3O+]=9.5×10−9M. Express the pH of the solution to two decimal places.

Respuesta :

When Ph = -㏒[H+] and when we have [H+] represents by [H3O+]= 9.5x10^-9 M
as the Ph is equal the negative ㏒ of the concentration of H+ ions or H3O+ hydronium ions.

So, by substitution in Ph equation:
∴ Ph = -㏒(9.5x10^-9)
         = 8.02 
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