Question

What is the range of the function f(x)=12-3x for the domain {-4,-2,0,2,4}?

Answer 1

F(-4)=12-3*(-4)=12+12=24
F(-2)=12-3*(-2)=12+6=18
F(0)=12-3(0)=12-0=12
F(2)=12-3*(2)=12-6=6
F(4)=12-3*(4)=12-12=0

The answer is{24,18,12,6,0}

Answer 2

f(-4) = 12 - 3*(-4) = 12 +12 = 24
f(4) = 12 - 3*4 = 12 -12 = 0

The range is like the difference between the greatest and smallest values in the domain, so just take the extreme values.

So the answer would be the last option.

Hope this helps !

Photon