Question

What is the molar mass of tetraethyl lead, Pb(C2H5)4? show your work please

Answer 1

M(Pb(C2H5)4 = M(PB)*1 + 4*( M(C)*2 + M(H)*5)
M(Pb(C2H5)4 = 207.2 + 4(12.0*2 + 1.0*5)
M(Pb(C2H5)4 = 207.2 + 4(28.0 + 5)
M(Pb(C2H5)4 = 207.2 + 4*33
M(Pb(C2H5)4 = 207.2 + 132
M(Pb(C2H5)4 = 339.2 g/mol

Hope this helps !

Photon

Answer 2

The molar mass of tetraethyl lead is 323.2 g

pb= 207.2

c= 12

h= 1

Pb(C2H5)4

207.2(12×2+1×5)4

207.2(24+5)4

207.2(29)4

207.2 + 116

= 323.2g

Hence the molar mass of tetraethyl lead is 323.2 g

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