To solve we can use Poisson probability formula:
[tex]P(x,\mu)=\frac{e^{-\mu}\mu^x}{x!} [/tex]
[tex]\mu[/tex] is the mean value of successes that happen in a given region.
x is the number of successes that are actually occurring in the given region. In our case x is 5, 4, 3, 2, 1 and 0. If a painter made 5, 4, 3, 2, 1 or no mistakes he made fewer than 6 mistakes. As these events are exclusive (you can't make 2 and 5 mistakes at the same time) we just add all those probabilities.
[tex]\mu[/tex] in our case is 4.8.
The final answer would be:
[tex](P(5)+P(4)+P(3)+P(2)+P(1)+P(0))=0.60[/tex]