Question

What is the volume of 0.30 M NaOH(aq) needed
to completely neutralize 15.0 milliliters of
0.80 M HCl(aq)?
(1) 3.6 mL (3) 20. mL
(2) 5.6 mL (4) 40. mL

Answer 1

(4) 40. mL is the correct answer.

Answer 2

Answer:  4) 40 ml

Solution :

According to the neutralization law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of NaOH solution = 0.30 M

$V_1$ = volume of NaOH solution = ?

$M_2$ = molarity of HCl solution = 0.80 M

$V_2$ = volume of HCl solution = 15 ml

Now put all the given values in the above law, we get the volume of NaOH solution.

$(0.30M)\times V_1=(0.80M)\times (15ml)$

$V_1=40ml$

Therefore, the volume of 0.30 M NaOH required to neutralize 15 ml of 0.80 M HCl is 40 ml.