[tex]\frac{6+3p}{2} - \frac{3}{4} (8 - 10p) \\ \\ \frac{6 + 3p}{2} - \frac{3(8-10p)}{4} \\ \\ \frac{6+3p}{2} - \frac{3 \times 2(4 - 5p)}{4} \\ \\ \frac{6+3p}{2} - \frac{6(4-5p)}{4} \\ \\ \frac{6+3p}{2} - \frac{3(4-5p)}{2} \\ \\ \frac{6+3p - 3(4-5p)}{2} \\ \\ \frac{3(2 +p - 4 + 5p}{2} \\ \\ \frac{3(2 + (p + 5p) - 4)}{2} \\ \\ \frac{3(2+6p-4)}{2} \\ \\ \frac{3 \times 2 (1 + 3p-2)}{2} \\ \\ \frac{3 \times 2(3p - 1)}{2} \\ \\ \frac{6(3p -1 }{2} \\ \\ 3(3p - 1) \\ \\ Answer: \fbox {3(3p-1)} [/tex]
