let's write it first:
2+[tex] \frac{3}{4} [/tex]+[tex] \frac{3}{x} [/tex]=2 [tex] \frac{5}{8} [/tex]
let's substract 2 from both sides
[tex] \frac{3}{4} [/tex]+[tex] \frac{3}{x} [/tex]=[tex] \frac{5}{8} [/tex]
and let's substract [tex] \frac{3}{4} [/tex] from both sides too
[tex] \frac{3}{x} [/tex]=[tex] \frac{5}{8} [/tex]-[tex] \frac{3}{4} [/tex]
this is
[tex] \frac{3}{x} [/tex]=[tex] \frac{5}{8} [/tex]-[tex] \frac{6}{8} [/tex]
[tex] \frac{3}{x} [/tex]=[tex] \frac{-1}{8} [/tex]
let's multiply by x:
3=[tex] \frac{-1x}{8} [/tex]
and by8:
24=-x
x=24
that means that the question mark is -24!!!!