Question

How can one fifthx − 2 = one thirdx + 8 be set up as a system of equations?

A) 5y - 5x =10
3y - 3x =24

B ) 5y - 5x = -10
3y + 3x =24

C) 5y + x = -10
3y + x =24

D) 5y - x = -10
3y - x =24

Answer 1

C.5y+x=-10                                                                                                             3y+x=24                                                                                                                i hope that help 

Answer 2

Answer:

System of linear equations:

$5y-x=-10$

$3y-x=24$

D is correct

Step-by-step explanation:

Given: $\dfrac{1}{5}x-2=\dfrac{1}{3}x+8$

It is complex linear equation. To solve this linear equation using graph by making system of linear equation.

Left side equation makes one equation and right side makes another.

Equation 1:

$y=\dfrac{1}{5}x-2$

Now change into standard form of line

$ax+by=c$

$5y-x=-10$

Equation 2:

$y=\dfrac{1}{3}x+8$

Now change into standard form of line

$ax+by=c$

$3y-x=24$

System of linear equations:

$5y-x=-10$

$3y-x=24$