Question

Which missing item would complete this beta decay reaction?
 PLATO

Answer 1

Answer: $_{-1}^0\beta$

Explanation:  

General representation of an element is given as:   $_Z^A\textrm{X}$

where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

Beta decay : In this process, a neutron gets converted into a proton and an electron releasing a beta-particle. The beta particle released carries a charge of -1 units.

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

The given reaction would be represented as:

$_{43}^{98}\textrm{Tc}\rightarrow_{44}^{98}\textrm{Pb}+_{-1}^0\beta$

Answer 2

Answer: Option (a) is the correct answer.

Explanation:

The high energy electrons are known as beta particles. Charge on a beta particle is -1, that is, similar to the charge present in an electron.

Hence, symbol that represents a beta particle is $^{0}_{-1}\beta$.

For example, $^{98}_{43}Tc \rightarrow ^{98}_{44}Ru + ^{0}_{-1}\beta$

This reaction is a radioactive decay rection when $^{98}_{43}Tc$ on decaying gives $^{98}_{44}Ru$along with emission of a beta particle.

Whereas $^{4}_{2}He$ is an alpha particle,  $^{0}_{0}\gamma$ is a gamma particle, and $^{1}_{0}n$ is a neutron.

Thus, we can conclude that the particle $^{0}_{-1}\beta$ would complete this given beta decay reaction.