Question

Determine the solubility of co2 in soda water at 25°c if the pressure of co2 is 5.6 atm. the henry's law constant for carbon dioxide in water at this temperature is 3.4 × 10-2 m/atm.

Answer 1

Solubility is estimated either in grams per 100 g of dissolvable – g/100 g – or number of moles per 1 L of the solution. 
So making this a formula, it would be: 
solubility = kH X P 
solubility = 3.4X10^-2 M/atm X 5.6 atm = 0.19 M is the solubility of carbon dioxide

Answer 2

Answer : The solubility of $CO_2$ is, 0.19 mole/L

Explanation :

The formula used for henry's law is:

$S_{CO_2}=k_H\times p_{CO_2}$

where,

$S_{CO_2}$ = solubility of $CO_2$ = ?

$p_{CO_2}$ = partial pressure of $CO_2$ = 5.6 atm

$k_H$ = Henry's law constant = $3.4\times 10^{-2}m/atm$

Now put all the given values in the above formula, we get:

$S_{CO_2}=(3.4\times 10^{-2}m/atm)\times (5.6atm)$

$S_{CO_2}=0.19mole/L$

Therefore, the solubility of $CO_2$ is, 0.19 mole/L