Question

45 points! Please show work!

Two point charges of +30.0 μC and -9.00 μC are 20.0 cm apart, with the negative charge to the right of the positive charge. Taking to the right as being the positive x-direction, what is the electric field midway between these two charges?

Answer 1

  E = Σkq/r²
=  9.0x10^9*(30x10^-6/0.10² -9.0x10^-5/0.10²) 
= 1.89x10^7N/C