a 40 kg-skier starts at the top of a 12-metter high slope. at the bottom she is travling 10 m/s. how much energy dose she lose to friction

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02-02-2018
Physics

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a 40 kg-skier starts at the top of a 12-metter high slope. at the bottom she is travling 10 m/s. how much energy dose she lose to friction

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AL2006 AL2006 · Answer 1 · 2018-02-02T01:39:23+01:00

Potential energy at the top = (mass) x (gravity) x (height)

= (40 kg) x (9.8 m/s²) x (12 m)

= 4,704 Joules

Kinetic energy at the bottom = 1/2 (mass) x (speed)²

= 1/2 (40 kg) x (10 m/s)²

= 2,000 Joules .

Energy lost between the top and the bottom

(4,704 joules) - (2,000 joules)

= 2,704 Joules