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One electrician charges a $50 service call fee plus $25 per hour for labor. Another electrician charges a $35 service call fee plus $27.50 per hour for labor. How long would a job take if the total cost for each electrician is the same?

Respuesta :

Let us first make expressions for each electrician.

Electrician 1:

Service call fee charged by first electrician =$50

Per hour labor charges =$25

let us say he worked for x hours.

Total cost = 50 +25x ...............(1)

Electrician 2:

Service call fee charged by second electrician =$35

Per hour labor charges =$27.50

let us say he worked for x hours.

Total cost = 35 +27.50 x.............. (2)

Since total cost is same for x hours, so equating equations (1) and (2)

[tex] 50 +25x= 35 +27.50x [/tex]

[tex] 50 -35= 27.50x -25x[/tex]

[tex] 15=2.50x [/tex]

dividing both sides by x

x = 6

Answer : A job would take 6 hours if the total cost for each electrician is the same.


The number of hours it would take the total cost of each electrician to be the same is 6 hours.

The total cost of the electricians is made up of fixed cost and variable cost.  The fixed cost of the electrician is the service call fee and the variable cost is the cost per hour of labor.

Total cost of the first electrician:  $50 + $25h

Total cost of the second electrician: $35 + $27.50h

Where h represents the total hours worked.

In order to determine the time when the total cost of each electrician would be the same, equate the expression for each electrician together.

$50 + $25h  =  $35 + $27.50h

Combine similar terms

$50 - $35 = $27.50h - $25h

$15 = $2.50h

h = $15 / 2.50

h = 6 hours

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