Question

Hey guys, mind helping me out on radicals?
Here's a problem to solve;

√64$m^{2}$$n^{3}$$p^{4}$

Could you explain this from beginning to end? I'm kinda lost, and a thorough explanation would help a bunch :))

Answer 1

to find the root, you must find out each numbers and variables squared

for example, rt(64) = 8, for 8 x 8 = 64
rt(m^2) is m, for m x m = m^2
rt(n^3) is n√n, for n x n x n = n^3, and only pairs of number (or variables) can be take out
rt(p^4) is p^2, for p x p x p x p = p^4

so your answer is 

8mnp²√n

8p²mn√n is your answer

hope this helps