Question

1. Which point on the axis satisfies the inequality y
- (0,1)
- (-1,0)
- (1,0)
- (0,0)


2. I the graph of the inequality x-2y>=4, which is a value for x on the boundary line and the x axis?

- 4
- -2
- 2
- -2


3. If x >=0 and y>=0, then which quadrant holds the solution?

- IV
- III
- I
- II


4. Which ordered pair is a solution of the inequality?
y>=4x-5

- (3,4)
- (2,1)
- (3,0)
- (1,1)


5. Write an inequality to match the graph.

- y<-5x+3
- y>5x+3
- y<5x+3
- y>-5x+3

Answer 1

1.) C - (1, 0)
2.) A - 4
3.) C - 1
4.) D - (1, 1)
5.) D

Answer 2

Answer:

1) Point $(1,0)$ -----> see the attached figure N $1$

2) The value of x is $4$

3) I quadrant

4) $(1,1)$

5)  $y>-5x+3$

Step-by-step explanation:

Part 1)

we know that

If the point satisfy the inequality

then

the point must be included in the shaded area

The point $(1,0)$ is included in the shaded area

Part 2)

we have

$x-2y\geq 4$

see the attached figure N $2$

we know that

The value for x on the boundary line and the x axis is equal to the x-intercept of the line $x-2y= 4$

For $y=0$

Find the value of x

$x-2(0)= 4$  

$x=4$

The solution is $x=4$

Part 3)

we have

$x\geq 0$ -----> inequality A

The solution of the inequality A is in the first and fourth quadrant

$y\geq 0$ -----> inequality B

The solution of the inequality B is in the first and second quadrant

so

the solution of the inequality A and the inequality B is the first quadrant

Part 4) Which ordered pair is a solution of the inequality?

we have

$y\geq 4x-5$

we know that

If a ordered pair is a solution  of the inequality

then

the ordered pair must be satisfy the inequality

we're going to verify all the cases

case A) point $(3,4)$

Substitute the value of x and y in the inequality

$x=3,y=4$

$4\geq 4(3)-5$

$4\geq 7$ ------> is not true

therefore

the point $(3,4)$ is not a solution of the inequality

case B) point $(2,1)$

Substitute the value of x and y in the inequality

$x=2,y=1$

$1\geq 4(2)-5$

$1\geq 3$ ------> is not true

therefore

the point  $(2,1)$ is not a solution of the inequality

case C) point $(3,0)$

Substitute the value of x and y in the inequality

$x=3,y=0$

$0\geq 4(3)-5$

$0\geq 7$ ------> is not true

therefore

the point  $(3,0)$ is not a solution of the inequality

case D) point $(1,1)$

Substitute the value of x and y in the inequality

$x=1,y=1$

$1\geq 4(1)-5$

$1\geq -1$ ------> is true

therefore

the point  $(1,1)$ is  a solution of the inequality

Part 5) Write an inequality to match the graph

we know that

The equation of the line has a negative slope

The y-intercept is the point $(3,0)$

The x-intercept is a positive number

The solution is the shaded area above the dashed line

so

the equation of the line is $y=-5x+3$

The inequality is  $y>-5x+3$