Multiply the length and width together:
3 2 6
A = ------ * ------ = --------
5 5 25
None of the given possible answers make any sense. Please ensure that you have copied down this problem exactly as presented.
If the width were 2/5 in and the length 3/5 in, then, using decimal fractions, the area would be
A = 0.4(0.6) = 0.24 in^2, which is miles and miles away from 15 in^2 (for example)