a canoe is floating down a river with a velocity of 35 meters per minute when it suddenly approaches a waterfall. if the waterfall drop 30 meters, how far put will the canoe land?
From Newton's law v^2 = u^2 + 2as where a is the acceleration and s is the distance. But to go any further, we need to know how fast the vehicle is accelerating From v = u +at We have a = u/t where the final velocity v = 0
So in one minute acceleration = (35 / 60) / 60 = 0.0097 ms/2. The first experession in bracket is the initial velocity, u, in metres per seconds. Hence v^2 = (0.583)^2 + 2 (0.0097)(30) v^2 = 0.3398 + 0.5826 = 0.9224 v = âš 0.9224 = 0.960m
