Respuesta :
Finding such an equation is a fundamental skill in Algebra, and I urge you to become proficient in it.
What I will do is find the slope of this line and then apply it in the point-slope formula for a straight line.
33-18
slope is m = --------- = 15/5 = 3
8-3
Then the eqn of the line is y-18 = 3(x-3).
You could rewrite this equation in other formats if you so wished.
What I will do is find the slope of this line and then apply it in the point-slope formula for a straight line.
33-18
slope is m = --------- = 15/5 = 3
8-3
Then the eqn of the line is y-18 = 3(x-3).
You could rewrite this equation in other formats if you so wished.
Answer: The equation of the line is,
[tex]y=3x+9[/tex]
Step-by-step explanation:
Since, the equation of a line passes through the points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is,
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
So, the equation of the line passes through the points (3, 18) and (8, 33) is,
[tex]y-18=\frac{33-18}{8-3}(x-3)[/tex]
[tex]y-18=\frac{15}{5}(x-3)[/tex]
[tex]y-18=3(x-3)[/tex]
[tex]y-18=3x-9[/tex]
[tex]y=3x+9[/tex]