Answer:
The correct option is c.
Step-by-step explanation:
The given expression is
[tex]^{12}C_{8}[/tex]
Combination formula:
[tex]^{n}C_{r}=\frac{n!}{r!(n-r)!}[/tex]
Using the formula we get
[tex]^{12}C_{8}=\frac{12!}{8!(12-8)!}[/tex]
[tex]^{12}C_{8}=\frac{12\times 11\times 10\times 9\times 8!}{8!(4)!}[/tex]
[tex]^{12}C_{8}=\frac{12\times 11\times 10\times 9}{4\times 3\times 2\times 1}[/tex]
[tex]^{12}C_{8}=495[/tex]
Therefore the correct option is c.
