Answer:
[tex](x^2+43x+10)-(-10x^2-5x+10)=11x^2+48x[/tex]
Step-by-step explanation:
Given polynomial [tex](x^2+43x+10) \ and \(-10x^2-5x+10)[/tex]
We have to subtract the given polynomials.
Consider [tex](x^2+43x+10) \ and \(-10x^2-5x+10)[/tex]
Subtract (1) - (2) , we have,
[tex](x^2+43x+10)-(-10x^2-5x+10)[/tex]
rewrite by applying plus-minus rule [tex]-(-a)=a[/tex] , we have,
[tex]x^2+43x+10+10x^2+5x-10[/tex]
Grouping like terms, (like term are terms with same variable having same degree)
[tex]=x^2+10x^2+43x+5x+10-10[/tex]
[tex]\mathrm{Add\:similar\:elements:}\:43x+5x=48x[/tex]
[tex]=x^2+10x^2+48x+10-10[/tex]
[tex]\mathrm{Add\:similar\:elements:}\:x^2+10x^2=11x^2[/tex]
[tex]=11x^2+48x+10-10[/tex]
Solving , we get,
[tex]=11x^2+48x[/tex]
Thus, [tex](x^2+43x+10)-(-10x^2-5x+10)=11x^2+48x[/tex]
