How many milliliters of a 3.0 M HCl solution are required to make 250.0 milliliters of 1.2 M HCl? 250.0 milliliters 100.0 milliliters 62.5 milliliters 0.1 milliliters

Respuesta :

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Answer:

100.0 milliliters

Explanation:

Using the dilution formula,  

M₁V₁ = M₂V₂  

Where M₁ and M₂ are the initial and final molarity, V₁ and V₂ are the initial and final volume.

V₁ = 250 ml

M₁ = 1.2 M

M₂ = 3M  

Plugging in the numbers in the dilution formula we get,  

1.2 M x 250 ml = 3M x V₂

V₂ = [tex]\frac{1.2 M x 250 ml}{3M}[/tex] = 100 ml

Therefore, 100 ml of a 3.0 M HCl solution are required to make 250.0 milliliters of 1.2 M HCl.

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