Question

What is the conjugate?
Sqrt 8 - sqrt 9

Answer 1

 The conjugate of an irrational number is the number you have to multiply it by in order to arrive at a rational number. 

Answer 2

Answer:

$\frac{-1}{(\sqrt{8}+\sqrt{9})}$

Step-by-step explanation:

We are given the expression $\sqrt{8}-\sqrt{9}$.

So, the conjugate is given by,

$(\sqrt{8}-\sqrt{9})\times \frac{(\sqrt{8}+\sqrt{9})}{(\sqrt{8}+\sqrt{9})}$

i.e. $\frac{(\sqrt{8})^{2}-(\sqrt{9})^{2}}{(\sqrt{8}+\sqrt{9})}$

i.e. $\frac{8-9}{(\sqrt{8}+\sqrt{9})}$

i.e. $\frac{-1}{(\sqrt{8}+\sqrt{9})}$

Thus, the conjugate of the expression is given by $\frac{-1}{(\sqrt{8}+\sqrt{9})}$.