Question

Find x-component of a⃗ = (4.5 m/s2, negative x-direction).

Answer 1

The first thing you should do in this case is to write the vector acceleration in its vector form.
 We have then:
 a = lal * (- i)
 Substituting
 a = l4.5l * (- i) m / s ^ 2
 rewriting:
 a = -4.5 * (i) m / s ^ 2
 a = -4.5 i m / s ^ 2
 answer:
 x-component of a⃗ is:
 a = -4.5 i m / s ^ 2

Answer 2

The acceleration is $\rm \vec{a} = -4.5 \hat{i}$.

Acceleration

Acceleration is the rate of change of the velocity is called acceleration. It is a vector quantity that depends on the magnitude and direction. If the acceleration is in a positive direction then it is taken as positive and if the acceleration is negative direction then it is taken as negative.

Velocity

It s the rate of change of displacement is called velocity.

Given

$\rm \vec{a}_x$ = (4.5 m/s2, negative x-direction).

Then according to the vector, the direction is very important.

$\rm \vec{a} = \vec{a}_x + \vec{a}_y$

here we have

$\rm \vec{a}_x$ = (4.5 m/s2, negative x-direction).

$\rm \vec{a}_y$ = 0 (becqause not given)

$\rm \vec{a} = -4.5 \hat{i}$

Thus, the acceleration is $\rm \vec{a} = -4.5 \hat{i}$.

More about the acceleration link is given below.

https://brainly.com/question/12134554