Question

ruby tosses a quarter off the main stree bridge into the st john`s river the distance in feet the quarter is above the water is modulated by the equation d(t)= -16t^2+96t+112. what weight what the quarter tossed

Answer 1

The correct question is

From what height was the quarter tossed?

For t=0

d= -16t^2+96t+112- ------>112 feet------- > view the graphic attached

the answer is 112 feet

Answer 2

First of all we will assume there is a typo in the question and the question would be:

From what height was the quarter tossed?

To determine from what height was the quarter tossed we have to understand the equation that was given to us $d(t)=-16t^{2}+96t+112$ where $t$ would represent the time in seconds. Now the movement of the coin (tossing) would be described in physics as a projectile motion where the coin would first go up and then fall to the river. We are asked from wich height was the coin tossed and this would be the height of the bridge, this could be solved by making $t=0$ because it is when we start the movement and would be from where we started it, we can see it better in the attached graph . Like this:

$d(0)=-16(0)^{2}+96(0)+112=0+0+112=112 ft$