Question

Which of the following are solutions to equation below.(check all that apply)
25x^2-16=0
A. 4
B. 5/4
C. 4/5
D. -4/5
E. -5/4
F. -4

Answer 1

x = 4/5 = 0.800

x = -4/5 = -0.800

C & D :)

Hope this helps!

-Lilly

Answer 2

Solutions to equation $25x^{2} -16=0$ is equals to $\frac{4}{5}$ and $\frac{-4}{5}$.

What is quadratic equation?

" Quadratic equation is defined as polynomial in which highest degree of the present variable is two."

Identity used

$a^{2} -b^{2} = (a-b)( a + b)$

According to the question,

Given quadratic equation,

$25x^{2} -16=0$

⇒$(5x)^{2} -(4)^{2} =0$

Apply identity in the quadratic equation we get,

$(5x-4)(5x+ 4) =0$

⇒$(5x-4)=0 or (5x+ 4) =0$

⇒$x= \frac{4}{5} or x= \frac{-4}{5}$

Hence, Option(C) and Option(D) are the correct answer.

Learn more about  quadratic equation here

https://brainly.com/question/2263981

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