Question

Sarah Worker is making a presentation. She has 81 people in a workshop. She selects 64. The average budget expense for groceries is 8%. Sarah wants her workshop group to calculate a 95% confidence interval for this estimated proportion. The confidence interval is from 2% to 14% (to the nearest percent).

TRUE OR FALSE???

Answer 1

True is the answer hope i help

Answer 2

Answer:

True. The confidence interval is between 2% and 14%

Step-by-step explanation:

p= 8% or 0.08

n= 64

$\sqrt{0.08(1-0.08)/64}$

$\sqrt{0.0736/64}$= 0.03391; round to nearest hundredth = 0.03 Standard Error

$0.08 +/- (1.96) (0.03)=$

0.08 + 0.0588= 0.1388= 13.88%= 14%

0.08 - 0.0588= 0.0212= 2.12%= 2%

move the decimals 2 places and round to the nearest whole number to get the percentage