Respuesta :
Answer:
Real and inverted
Explanation:
Magnification of a lens is defined as the ratio of the height of the image to the height of the object.
[tex]m=\dfrac{h'}{h}[/tex]
Where
h' is the height of image
h is the height of the object
It is also defined as the ratio of image distance to the object distance.
[tex]m=\dfrac{-v}{u}[/tex]
Here, m = -0.6
Negative sign shows the image is inverted. So, the formed image will be real and inverted.
Answer:
Real, Inverted and diminished
Explanation:
Magnification of the image formed by the lens is given as
m = -0.6
magnification is defined as the ratio of length of image and object.
So we can say that magnification is
[tex]m = \frac{height_{image}}{height_{object}}[/tex]
so we can say that here
[tex]height_{image} = -0.6 height_{object}[/tex]
so we can say that
image will be inverted and smaller in size with respect of object
Also we know that all inverted images are Real images
so the property of image is
Real, Inverted and diminished