Respuesta :

Answer:

Real and inverted

Explanation:

Magnification of a lens is defined as the ratio of the height of the image to the height of the object.

[tex]m=\dfrac{h'}{h}[/tex]

Where

h' is the height of image

h is the height of the object

It is also defined as the ratio of image distance to the object distance.

[tex]m=\dfrac{-v}{u}[/tex]

Here, m = -0.6

Negative sign shows the image is inverted. So, the formed image will be real and inverted.

Answer:

Real, Inverted and diminished

Explanation:

Magnification of the image formed by the lens is given as

m = -0.6

magnification is defined as the ratio of length of image and object.

So we can say that magnification is

[tex]m = \frac{height_{image}}{height_{object}}[/tex]

so we can say that here

[tex]height_{image} = -0.6 height_{object}[/tex]

so we can say that

image will be inverted and smaller in size with respect of object

Also we know that all inverted images are Real images

so the property of image is

Real, Inverted and diminished

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