An 80.0 kg hiker walks a distance of 400.0 m along a road that slopes 5.0 degrees upward, and then stops. What is the hiker's final gravitational potential energy relative to her original position? You may use a trigonometry table
The height difference is found by [tex]\delta H=400sin(5 \°)=34.86m[/tex] Then the change in potential energy is [tex]E=mgh=(80.0kg)(9.8 \frac{kgm}{s^2})(34.86)= 27332J[/tex]
