Answer:
The best approximation is [tex]201.0\ in^{2}[/tex]
Step-by-step explanation:
we know that
The area of the circle is equal to
[tex]A=\pi r^{2}[/tex]
In this problem we have
[tex]r=8\ in[/tex]
[tex]\pi =3.14[/tex]
substitute
[tex]A=(3.14)(8^{2})=201.0\ in^{2}[/tex]