Seudónimo Seudónimo
  • 30-01-2018
  • Mathematics
contestada

Factor. 3n4+21n3+27n2

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CastleRook
CastleRook CastleRook
  • 19-06-2018
To factor out the expression we look for number which is divisible by every term in our case it is 3n^2:
3n^4+21n^3+27n^2
we first begin by factoring out 3n^2, this will give us;
3n^2(n^2+7n+9)
hence, since we cannot factorize the quadratic expression the answer remains to be:
3n^2(n^2+7n+9)

Answer Link
savannahlynn07
savannahlynn07 savannahlynn07
  • 19-02-2021

Answer:

3n^2(n^2+7n+9)

Answer Link

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