Question

Write the standard form of the line that contains a slope of -3/8 and passes through the point (5, -4). Include your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution.

Answer 1

y - (-4) = -3/8(x - (5))
y + 4 = -3/8(x - 5)
The standard form is y + 4 = -3/8(x - 5)

Answer 2

Answer:

$y + \frac{3x}{8} = -\frac{17}{8}$

Step-by-step explanation:

Hello

we know a point and the slope , it is possible use the slope-point equation to find the function

$y-y_{0} =m(x-x_{0} )$

Let

$Point(5,-4)\\m=-\frac{3}{8}$

replacing

$y-y_{0} =m(x-x_{0} ) \\y-(-4) =-\frac{3}{8}(x-5 )\\y+4=-\frac{3x}{8}+ \frac{15}{8} \\y+4 =-\frac{3}{8}(x-5 )\\y+4=-\frac{3x}{8}+ \frac{15}{8}\\y + \frac{3x}{8} = \frac{15}{8}-4\\\\y + \frac{3x}{8} = -\frac{17}{8}$

the standard form is

$y + \frac{3x}{8} = -\frac{17}{8}$

Have a great day