Question

two consecutive negative integers have a product of 132 what are the integers ??

Answer 1

Let the two consecutive negative integers be x and x+1
Then, x(x+1) = 132 
x^2+x-132=0
(x+12)(x-11)=0
x=-12,11
So the two consecutive negative integers are -11,-12

Answer 2

X(x+1)=182

-14 and -13 are ur answers

Hope this helps on e2020