Respuesta :

[tex]\bf \textit{recall that }i^2=-1\\\\ -------------------------------\\\\ -2i\sqrt{-12}\quad \begin{cases} 12=2\cdot 2\cdot 3\\ \qquad 2^2\cdot 3 \end{cases}\implies -2i\sqrt{-1\cdot 2^2\cdot 3} \\\\\\ -2i\sqrt{-1}\cdot \sqrt{2^2}\cdot \sqrt{3}\implies -2i\cdot i\cdot 2\cdot \sqrt{3}\implies -4i^2\sqrt{3} \\\\\\ -4(-1)\sqrt{3}\implies 4\sqrt{3}[/tex]
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