In baseball,the pitcher's mound is 60'6 feet from home plate,center field is 350' from home plate,and the distance between each base is 90'.What is the distance between home plate and second base?
This problem can be seen as a rectangle triangle where the vertices are: Vertice 1: home plate Vertice 2: First base Vertice 3: second base. Right angle between vertice 1 and 2 and vertice 2 and 3. Distance between each base in 90 '. Calculating then the distance between home plate and second base we have: d = root ((90) ^ 2 + (90) ^ 2) d = 127.28 feets answer: the distance between home plate and second base is 127.28 feets
